Monday, September 8, 2008

Problem 2.60

Before you do this problem make sure to go over the cop/speeder problem that we did in class.

The only difference here is that the bicycle which passes the stationary bicycle moves an EXTA 2 seconds. So you have to account for this extra 2 seconds in the equation for distance traveled.

Your final equation will be a quadratic equation, which you should be able to solve.

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