Problem 4.15 IP A white-crowned sparrow flying horizontally with a speed of 1.90 folds its wings and begins to drop in free fall. How far does the sparrow fall after traveling a horizontal distance of 0.600 ?
a= -9.8 Vx=1.90 Viy= 1.90 dx=.600 dy=?
so i found the time using dx=vx.t I used that time to apply ir to the formula dy=Vi.t+.5 (-9.8.t^2) What Am i doing wrong?
3 comments:
Problem 4.15
IP A white-crowned sparrow flying horizontally with a speed of 1.90 folds its wings and begins to drop in free fall. How far does the sparrow fall after traveling a horizontal distance of 0.600 ?
a= -9.8
Vx=1.90
Viy= 1.90
dx=.600
dy=?
so i found the time using dx=vx.t
I used that time to apply ir to the formula dy=Vi.t+.5 (-9.8.t^2)
What Am i doing wrong?
Viy should be zero
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