Saturday, August 30, 2008
Problem 1.39B
The problem gives the number of wing beats in one second. Using this, find the the time it takes for one wing beat. Similarly, given that there are 9,192,631,770 cesium-133 oscillations in one second, find the time for one oscillation. The number of cesium oscillations that occur during one wing beat is just: time for one wing beat/ time for one cesium oscillation.
Friday, August 22, 2008
Physics 100a
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